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Q: What is sin 45?

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Assuming that the angles are all stated in degrees: sin(45) = cos(45) = 1/2 sqrt(2) sin(45) cos(45) = (1/2)2 x (2) = 1/2 sin(230) = - 0.7660444 sin(45) cos(45) - sin(230) = 0.5 + 0.7660444 = 1.2660444 (rounded)

cos(45) = sin(45) You can see this as follows: imagine a circle with radius 1. The point on the circle with angle 45 degrees, lies on the line y=x, equally far from the x-axis (cos) as the y-axis (sin). The angle for both must be 45, because x and y are orthogonal: 90 deg, so if the angle with x is 45, then the angle with y must be 90-45=45. So: for this point, both angles are 45, and the distance to x (cos) is equal to the distance to y (sin). Therefore, cos(45) = sin(45). Additionally, cos(45) = sin(45+90) = sin(45+360n) = sin(135+360n) with n integer.

sin theta = opp/hyp sin 45 = opp/1 opp = sin 45 = sqrt(2)/2 ~= 0.7071

They are both trig values, but not equal. Tan 45 is 1 and sin 45 is 0.7071

45

If tan 3a is equal to sin cos 45 plus sin 30, then the value of a = 0.4.

sin(x) + cos(x) = sqrt(2) · sin(45°+x)

It is 1/2

This problem can be solved using the Sine Rule :a/sin A = b/sin B = c/sin C 10/sin 45 = AB/sin 75 : AB = 10sin 75 ÷ sin 45 = 13.66 units (2dp)

1 cot(theta)=cos(theta)/sin(theta) cos(45 degrees)=sqrt(2)/2 AND sin(45 degrees)=sqrt(2)/2 cot(45 deg)=cos(45 deg)/sin(deg)=(sqrt(2)/2)/(sqrt(2)/2)=1

to find sin 35 here we take the angle = x=15 then 3x=45 , 4x=60 then 4x-3x=60-45 then by putting sin on rhs we will get cos 35 and sin 35 hope it helped you

45 degree

= 1/sqrt(2) = 0.7071

1/square root 2

sin(45) = cos(45) = 1/sqrt(2) tan(45) = cot(45)= 1 csc(45) = sec(45) = sqrt(2)

sin(75) = sin(45 + 30) = sin(45)*cos(30) + cos(45)*sin(30) = [1/sqrt(2)]*[sqrt(3)/2] + [1/sqrt(2)]*[1/2] = 1/[2*sqrt(2)]*[sqrt(3) + 1] that is [sqrt(3) + 1] / [2*sqrt(2)]

If you mean "inscribed within", the formula is r/(√2 + √6). To see why this is true, consider a "slice" of the dodecagon - a triangle with corners at two connected corners of the dodecagon and at the center of the circle. Its sides are r, r, and s (the length of a side); the angles are 75, 75, and 30. By the Law of Sines, we have that s = r*sin(30)/sin(75). sin(75)=sin(30+45)=sin(30)cos(45)+cos(30)sin(45). We know the values for sine and cosine of 30 and 45; when we substitute them into the sin(30)/sin(75), we get 1/(√2 + √6). This gives us the formula above.

T=f*d*sin(of the angle) torque= 8*.5*sin(45) =2.828 NM

sin 105 = sin (60+45) = sin60cos45 + cos60sin45sin 105 = ((sqrt(3)/2)((sqrt(2)/2)) + ((1/2)((sqrt(2)/2)))sin 105 = (sqrt(6) + sqrt(2)) / 4

6.25

Sin(30) = 1/2 Sin(45) = root(2)/2 Sin(60) = root(3)/2 Cos(30) = root(3)/2 Cos(45) = root(2)/2 Cos(60) = 1/2 Tan(30) = root(3)/3 Tan(45) = 1 Tan(60) = root(3) Csc(30) = 2 Csc(45) = root(2) Csc(60) = 2root(3)/3 Sec(30) = 2root(3)/3 Sec(45) = root(2) Sec(60) = 2 Cot(30) = root(3) Cot(45) = 1 Cot(60) = root(3)/3

Assuming the angles are expressed in radians:sin(5x) + sin(x) = 0∴ sin(5x) = -sin(x)∴ 5x = x + π∴ x = π/4On the other hand, if your angles are in degrees, then the answer would be:sin(5x) + sin(x) = 0∴ sin(5x) = -sin(x)∴ 5x = x + 180∴ x = 180°/4∴ x = 45°

sin-1(0.707) = 44.99134834 or about 45 degrees

x = 45 degrees sin(x) = cos(x) = 1/2 sqrt(2)

Sin is sine. Cos is cosine. http://en.wikipedia.org/wiki/Sine_curve http://en.wikipedia.org/wiki/Cosine_curve In terms of trigonometric identities sin2A=2sinAcosA cos2A=cos2A-sin2A sin2A-cos2A=2sinAcosA-cos2A+sin2A === === sin(A) - cos(A) = sqrt(2)sin(A-45)

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