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Q: What is the algebraic expression for a number decreased by six?

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The answer for this problem is 6 - n.

As an expression it is: x-6

(6+n) n= a number

N + 6

6/n?

36 + n

The algebraic expression is 2m+6

2(-6n)

6*n+25

2x = 76 x = 38

It is: 6x-5

Let the number be x and so the algebraic expression is: 6x+2

6x

7X-6

6/n +2

3+ 6/n

You do not wright it, but write it as n + 6.

As an algebraic expression, six less than a number p is simply: p-6

k - 6

It is an algebraic expression in the form of 2x+6 whereas x is the unknown variable

G = C/6 where C is the number in the class and G is the number in each group.

The constant term.

7r-6

doubling the quantity of a number decreased by six is lessthan negative thirty six

3(y^2)-6

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