-6
3x-6y=9 -3x -3x -6y=9-3x __ ____ -6 -6 y=9-3x ____ -6
3x-y = 9 2x+y = 6 Add both equations together: 5x = 15 x = 3 and y = 0
-3x - 9 = 3y -x - 3 = y y = -(x+3)
9
y=-2/3x
3x-y=9 y=3x-9
y = 3x + y => x = 0then y = x - 9 => y = 0 - 9 = -9.
-9
3x-6y=9 -3x -3x -6y=9-3x __ ____ -6 -6 y=9-3x ____ -6
3x+y=-1 y=-1-3x5x-y=9 5x-(-1-3x)=95x+1+3x=98x=8x=1y=-1-3(1)y=-4(1,-4)
3x-y = 9 2x+y = 6 Add both equations together: 5x = 15 x = 3 and y = 0
your equation is y=3x + 4 here are five parallel equations... y=3x + 5 y=3x + 6 y=3x + 7 y=3x + 8 y=3x + 9
-3x - 9 = 3y -x - 3 = y y = -(x+3)
slope: -3 y-intercept: 9
3x+2y=9 2y=9-3x y=-1.5x-4.5
9
Let's solve this by substitution. We're told: 3x + y = 9 6x = 4 - 2y Let's start with the second equation, and solve for y: 6x = 4 - 2y 3x = 2 - y 2 - 3x = y Now we can substitute it into the first equation, replacing all occurrences of y with 2 - 3x: 3x + (2 - 3x) = 9 2 = 9 Ah! That of course makes no sense, which tells us that the lines do not intersect at all, but are in fact parallel to each other. Let's confirm that by rearranging each of them into standard form: 3x + y = 9 y = 9 - 3x y = -3x + 9 6x = 4 - 2y y = 2 - 3x y = -3x + 7 So there you have it. Those expressions describe two lines that have a slope of 3 and a y position that differs by 2.