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A example of a variable in math?
5n (also known as 5xn)=10, which means n=2. n is the variable. 5-n=2 which means n=3 5/n (I'm trying to say 5 over n, also known as 5 divided by n)=20, which means n=0.25. 5+n=7 n=2.
What is the answer for n plus 2 equals 5?
n + 2 = 5, solve for n.n = 5 - 2n = 3
What is the largest number of diagonals that can be drawn inside a polygon with n sides?
Formula: number of diagonals = 1/2 * n(n-3) where n is the number of sides or vertices Example: to get the number of diagonals in a pentagon pentagon has 5 sides or vertices; thus, n = 5 no. of diagonals: = 1/2 * n(n-3) = 1/2 * 5(5-3) = 1/2 * 5(2) = 1/2 * 10 = 10/2 = 5
When 5 is added to 2 times a number the result is 45 Find the number?
Let number be N, then 2 x N + 5 = 45 2 x N = 45 - 5 = 40 N = 20
Any number to the zero power is equivalent to?
1proof:n**3 * n**-3 = n**0n**3 = n*n*nn**-3 = 1/n * 1/n * 1/n1/n * 1/n * 1/n * n * n * n= n*n*n/(n*n*n) = 1Any number to the zero power = 1 .Any number to the ' 1 ' power = itself .Also:ex. 3^0 = 1but this is also the same value as :5^0 = 1Hence 3^0 = 5^0 = n^0 = 1If you had 3^2 / 3^2 the result is 1 since any value divided by itself it 1.Hence the base (here it's 3) and the exponent (here it's 2) is essentially eliminated and the result is just 1 as it would be for any other base and exponent. Mathematically, in an expression form you can eliminate (set to 0) the exponent by subtracting the exponents:3^2 / 3^2 = 1 = 3^(2-2) = 3^0 = 1 = n^0X^0=1How about this:If you had 5^2 / 5^2 , it equal 1 since any number divided by that same value is one. Therefore there is no power of 5 left since 5^1 would be 5. It is as if you subracted the exponents: 5^(2-2) = 5^0. This is valid because if you had something like:5^2 / 5^1 = 5^(2-1) = 5^125 / 5 = 5 = 5^1
What is 5 plus 3 plus 2 equals 5 plus 3 plus n?
That would be 18+n. 5+3+2 = 5+3+n 10 = 8 + n 10-8 = n 2 = n and if you substitute 2 for n then you see that 5+3+2 = 5+3+2
What is n over 2 plus 5 equal 3?
n ___ = 3 2+5 n = 3(2+5) n = 3(7) n = 21
Does a pentagon have 5 diagonals?
Yes. A polygon has n(n-3)/2 diagonals, so if n=5: 5(2)/2 =5
What is the product of 5 and m plus half of n?
If we are to find the product of 5 and m and n/2 (which is half of n), we have: 5 times m times n/2 = 5 x m x n/2 = 5mn/2
A example of a variable in math?
5n (also known as 5xn)=10, which means n=2. n is the variable. 5-n=2 which means n=3 5/n (I'm trying to say 5 over n, also known as 5 divided by n)=20, which means n=0.25. 5+n=7 n=2.
What is the answer for n plus 2 equals 5?
n + 2 = 5, solve for n.n = 5 - 2n = 3
What is the largest number of diagonals that can be drawn inside a polygon with n sides?
Formula: number of diagonals = 1/2 * n(n-3) where n is the number of sides or vertices Example: to get the number of diagonals in a pentagon pentagon has 5 sides or vertices; thus, n = 5 no. of diagonals: = 1/2 * n(n-3) = 1/2 * 5(5-3) = 1/2 * 5(2) = 1/2 * 10 = 10/2 = 5
N plus 2 equals 5 what does n equals?
5-2=3n=3
If 5 is added to a number n and the answer is multiplied by 2 the result will be 24 what is the number n?
Let's break this down step by step. If we add 5 to the number n, we get n + 5. When we multiply this sum by 2, we get 2(n + 5). Given that this result is equal to 24, we can set up the equation 2(n + 5) = 24. Solving for n, we find n = 7.
What is 7-n equals 2?
5
The sum of the squares of two consecutive odd integers is 74 find the two integers?
Let the integers be 'n' & 'n+2' Hence Their squares are n^(2) & (n+2)^(2) Their sum is n^(2) + (n+2)^(2) = 74 Expanding n^(2) + n^(2) + 4n + 4 = 74 2n^2 + 4n -70 = 0 n^2 + 2n - 35 = 0 Factor (n - 7)(n + 5) Hence n = '5' & '7' Odd and consecutive.
What multiplies to 20 but adds to be -9?
11
