2x+y = 10 or y = -2x + 10 so the slope is -2
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
12
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
y = -2x+10
2x+y = 10 or y = -2x + 10 so the slope is -2
2x-5y = -10 -5y = -2x-10 y = 2/5x+2 which is in slope intercept form
12
-5y +2x = -10 -5y = -2x -10 y = 2/5x +2 So the slope = 2/5 and the y intercept = 2
the slope is in front of the x when solved for y.y=2x-3The slope is 2.
2X - 5Y = 10 subtract 2X from each side - 5Y = - 2X + 10 divide each side by - 5 Y = 2/5X - 2 slope(m) = 2/5
To solve this, present the equation in the standard slope/intercept form of y = mx + c. 'm' is the slope. 2x + 5y = 10 5y = -2x + 10 y = -2/5x + 2 Therefore, -2/5 is the slope.
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
y = -2x+10
Slope-Intercept Form: y = -2x +1
Put in this form. Y = mX + c 2X - 5Y = 10 - 5Y = - 2X + 10 Y = (2/5)X - 2 ================