2*2*3*17= 204
2 x 2 x 17 is the prime factorization of 68.
2 x 986 4 x 493 17 x 116 29 x 68 34 x 58 2 x 2 x 493 2 x 17 x 58 2 x 29 x 34 4 x 17 x 29 2 x 2 x 17 x 29
136 = 2 * 2 * 2 * 17 = 2^3 * 17 2 x 2 x 2 x 17 = 136
4x + 17 = x + 2 4x - x = 2 - 17 3x = -15 x = -5
2 x 2 x 13 x 17 = 884
2, 5 and 17
For 510: 2, 3, 5 and 17 For 544: 2 and 17
The two numbers that multiply to equal 34 are 1 and 34. This is because 1 multiplied by 34 equals 34. In this case, both numbers are factors of 34, and when multiplied together, they result in the given product.
Its 2x2x17.2*2*17
|x-19|=17 x-19=17 x=36 x-19=-17 x=2 x=19 amd x=2
In the rectangle ABCD, let the length be x, so the width will be 17 - x (17 = 1/2 of the perimeter). In the right triangle ABC, we have:1. The length measure of AB = x (leg)2. The length measure of BC = 17 - x (leg)3. The length measure of AC = 13 (hypotenuse) From the Pythagorean Theorem we have: 13^2 = x^2 + (17 - x)^213^2 = x^2 + 17^2 - 2(17)(x) + x^2169 = 2x^2 + 289 - 34x0 = 2x^2 - 34x + 1200 = x^2 - 17x + 60x = [[-(-17) ± √[17^2 - 4(1)(60)]]/(2)(1)x = [17 ± √(289 - 240)]/2x = (17 ± √49)/2x = (17 ± 7)/2x = (17 + 7)/2 or x = (17 - 7)/2x = 24/2 or x = 10/2x = 12 or x = 5 17 - x = 17 - 12 or 17 - x = 17 - 5 17 - x = 5 or 17 - x = 12Thus, the length measure is 12 m, and the width measure is 5 m, orthe length measure is 5 m, and the width measure is 12 m.