Equations can be solved, but you have not given us an equation, just a term. The most typical form for an algebraic equation would be to start with zero, so perhaps you intended to say, 129x - 6 = 0 which would then be easy to solve. Add 6 to both sides, 129x = 6 then divide both sides by 129, x = 6/129 which we can simplify to 2/43. This expression can be represented as a linear equation in two variables. Let's impose another variable, say y. Then we have y = 129x - 6 which has infinitely many solutions of the form (x, y). Pick a value for x and input it into the equation to obtain a corresponding value for y. There are two special solutions, (2/43, 0) and (0, -6), which lies on the x- and y-axis.
a = 3 and y = 0
y=9x=3it equals ......y= 3.334
The y-intercept equals 0.
y=10
Equations can be solved, but you have not given us an equation, just a term. The most typical form for an algebraic equation would be to start with zero, so perhaps you intended to say, 129x - 6 = 0 which would then be easy to solve. Add 6 to both sides, 129x = 6 then divide both sides by 129, x = 6/129 which we can simplify to 2/43. This expression can be represented as a linear equation in two variables. Let's impose another variable, say y. Then we have y = 129x - 6 which has infinitely many solutions of the form (x, y). Pick a value for x and input it into the equation to obtain a corresponding value for y. There are two special solutions, (2/43, 0) and (0, -6), which lies on the x- and y-axis.
a = 3 and y = 0
y=9x=3it equals ......y= 3.334
x equals y
y=9
The y-intercept equals 0.
-17 + y,,must be equals to..-17y..
y=10
x equals -12 and y equals 1/4 of -12, so y = -3.
Transitive property: If 8 equals x and x equals y, then 8 equals y.
648
x equals half y