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According to Wolfram Alpha, input:integral csc x

it is -log[cot(x) + csc(x)] + constant

You can verify this by taking the derivative of the purported integral.

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The anti-derivative of cscx is secx.

Q: What is the anti-derivative of co secant x?

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By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2

(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)

Secant is a trignometric function. In a right triangle, the secant of an angle is the hypotenuse over the adjacent side. It is also the inverse of cosine. For example secant(x) = 1/cos(x)

It is the reciprocal of the sine ratio.

2*pi radians.

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Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C

By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2

Elephant

(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)

-e-x + C.

It is -exp (-x) + C.

Secant is a trignometric function. In a right triangle, the secant of an angle is the hypotenuse over the adjacent side. It is also the inverse of cosine. For example secant(x) = 1/cos(x)

It is 360 degrees.

2*pi radians.

It is the reciprocal of the sine ratio.

cosecant(x) = 1/sin(x) = -1sin(x) = -1x = 270 degrees(plus or minus any whole multiple of 360 degrees)

That's right. cosecant(x) = 1 / sine(x), so you would get a division by zero.