According to Wolfram Alpha, input:integral csc x
it is -log[cot(x) + csc(x)] + constant
You can verify this by taking the derivative of the purported integral.
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)
Secant is a trignometric function. In a right triangle, the secant of an angle is the hypotenuse over the adjacent side. It is also the inverse of cosine. For example secant(x) = 1/cos(x)
2*pi radians.
It is the reciprocal of the sine ratio.
Antiderivative of x/-1 = -1(x^2)/2 + C = (-1/2)(x^2) + C Wolfram says antiderivative of x^-1 is log(x) + C
By antiderivative do you mean integral? If yes, integral x^1 dx= (x^2)/2
Elephant
(that weird integral or antiderivative sign) x^(-6/5) dx =-5*x^(-1/5)
It is -exp (-x) + C.
-e-x + C.
Secant is a trignometric function. In a right triangle, the secant of an angle is the hypotenuse over the adjacent side. It is also the inverse of cosine. For example secant(x) = 1/cos(x)
It is 360 degrees.
2*pi radians.
It is the reciprocal of the sine ratio.
cosecant(x) = 1/sin(x) = -1sin(x) = -1x = 270 degrees(plus or minus any whole multiple of 360 degrees)
The general formula for powers doesn't work in this case, because there will be a zero in the denominator. The antiderivative of 1/x is ln(x), that is, the natural logarithm of x.