Surface area = 2 x area_triangular_ends + areas_of_3_rectangular_faces Surface area = 2 x (15 x 20)/2 + 30 x 15 + 30 x 20 + 30 x 25 = 15 x 20 + 30 x (15 + 20 + 25) = 300 + 30 x 60 = 2100 in2
The area of rectangles (including squares) is given by length x width. for the square 20 x 20, its area is 20 x 20 = 400 For the rectangle 10 x 30, its area is 10 x 30 = 300 If the shapes are divided up into 10 x 10 squares, it can be seen that the square has four of them, where as the rectangle will only have three: ................................................. ......20 x 20..........10 x 30.......... .....---------.......-------------.... .....|.....|.....|......|.....|.....|.....|.... .....|.....|.....|......|.....|.....|.....|.... .....|---+---|......-------------.... .....|.....|.....|.............................. .....|.....|.....|..Each little square.. .....---------.......is 10 x 10......... .................................................
For a rectangle, the area is the length times the width. A = L x W = 20 x 30 = 600 square feet
20' x 30' = 600. 600 sf.
600
23 x 20 x 30 = 13,800
30-ft x 20-ft = 600 square feet
20 x 30 computed in square meters (m²) isn't simply 20 x 30. Here's why: 20 and 30 represent lengths in centimeters (cm) based on the context of seat covers and textile measurements typically done in centimeters. Square meters (m²) is a unit of area, requiring multiplication of length and width. Since we don't have the width of the material, we cannot directly calculate the area in square meters. If you have the width in centimeters as well, you can multiply it by 20 (length in cm) to get the area in square centimeters. Then, divide that result by 10,000 (because there are 100 centimeters in 1 meter) to convert the area to square meters.
(2/3) x (-30) = -20
20% of 30 is 6 ; 20 percent = .20 30 x .20 = 6
Length=30 cm Width=20cm Original Area= ?? Original Area = (Length)(Width) Original Area = (30cm)(20cm) Original Area = (600sq.cm) New Area = 2(Original Area) New Area = 2(600sq.cm) New Area = 1200sq.cm Let X = Extra Width New Area = (X+L)(X+W) 1200= (X+30)(X+20) 1200= X^2+50X+600 0=X^2+50X+600-1200 X^2+50X-600=0 (X+60)(X-10)=0 X+60=0 X= -60cm (60cm is negative so this is not the width what were looking for because it's impossible to have a negative distance) X-10=0 X= 10cm (10 cm is positive so this is the width what were looking for) Checking: New Area = (X+L)(X+W) 1200 = (10+30)(10+20) 1200 = (40)(30) 1200 = 1200
20 x 30 = 600 square cm