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What is the area of a quadrilateral in cm with coordinates at 4 0 and 14 11 and 0 6 and -10 -5 on the Cartesian plane?
Wiki User
∙ 6y ago
The given coordinates of (4, 0) (14, 11) (0, 6) and (-10, -5) when plotted and joined together on the Cartesian plane will form into the shape of a kite with its diagonals meeting at right angles and by using the area formula 0.5*product of its diagonals the area of the quadrilateral kite works out as 104 square cm
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is 104 square units. Area cannot be measured in cm and, in any case, there is no direct conversion between coordinates and centimetres.
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What is the area of a quadrilateral with coodinates at -1 4 and 3 7 and 5 2 and -5 -17?
Coordinates: (-1, 4) (3, 7) (5, 2) (-1, 4) When plotted on the Cartesian plane its diagonals of 2 times square root of 10 and 8 times square root of 10 will intersect each other at right angles. Area of the quadrilateral: 0.5 times the product of its diagonals = 80 square units
How can you identifies quadrilateral?
A quadrilateral is a plane area enclosed by four straight lines.
What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -4 -17 respectively on the Cartesian plane?
Its diagonals intersect each other at right angles when plotted on the Cartesian plane Its diagonal lengths are 2 times square root of 10 and 8 times square root of 10 Its area is 0.5 times product of its diagonals equals 80 square units
What are the corner angles and area of a quadrilateral with vertices at -1 4 and 3 7 and 8 7 and 4 4 on the Cartesian plane?
The given vertices will form a rhombus when plotted on the Cartesian plane with 4 equal sides of 5 units with 2 equal opposite angles of 143.13 degrees and 2 equal opposite angles of 36.87 degrees including an area of 15 square units.
What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -5 -17 giving the reason for your answer?
When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.
What is the area of a quadrilateral with coodinates at -1 4 and 3 7 and 5 2 and -5 -17?
Coordinates: (-1, 4) (3, 7) (5, 2) (-1, 4) When plotted on the Cartesian plane its diagonals of 2 times square root of 10 and 8 times square root of 10 will intersect each other at right angles. Area of the quadrilateral: 0.5 times the product of its diagonals = 80 square units
How can you identifies quadrilateral?
A quadrilateral is a plane area enclosed by four straight lines.
What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -4 -17 respectively on the Cartesian plane?
Its diagonals intersect each other at right angles when plotted on the Cartesian plane Its diagonal lengths are 2 times square root of 10 and 8 times square root of 10 Its area is 0.5 times product of its diagonals equals 80 square units
What is the definition of quadrilateral?
A "quadralateral" may be defined as a typographic error for the word "quadrilateral".
What is a quadrilateral described as?
A quadrilateral is the shape of a 4 sided polygon
What are the corner angles and area of a quadrilateral with vertices at -1 4 and 3 7 and 8 7 and 4 4 on the Cartesian plane?
The given vertices will form a rhombus when plotted on the Cartesian plane with 4 equal sides of 5 units with 2 equal opposite angles of 143.13 degrees and 2 equal opposite angles of 36.87 degrees including an area of 15 square units.
What is the area of the quadrilateral with vertices at 8 9 and 1 9 and 10 3 and 1 3?
The 4 sided quadrilateral will form a right angled trapezoid when plotted on the Cartesian plane with parallel sides of 7 units and 9 units with a height of 6 units. Area of trapezoid: 0.5*(7+9)*6 = 48 square units.
What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -5 -17 giving the reason for your answer?
When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.
How can coordinates help you to find the area of figures on the coordinate plane?
Once you know the coordinates, you can use the distance formula to find the lengths of the sides, then using that, you can find the area.
What are the interior angles and area of a triangle with vertices at 5 9 and 14 -3 and 2 3 on the Cartesian plane?
Plotting the given vertices on the Cartesian plane results in a right angle triangle with angles of 90 degrees, 26.565 degrees and 63.435 degrees including an area of 45 square units.
What is the centre and area in cm of a circle whose circumference cuts through the points of 1 0 and 7 -6 and 7 0 on the Cartesian plane?
It works out that the centre of the circle is at (4, -3) on the Cartesian plane and its area is 56.549 square cm rounded up to three decimal places.
How do you find the area of a triangle whose vertices have the coordinates ( -1 -1) (-13) and (5 -1)?
If you mean vertices of: (-1, -1) (-1, 3) and (5, -1) then when plotted on the Cartesian plane it will form a right angle triangle with a base of 6 units and a height of 4 units. Area of triangle: 0.5*6*4 = 12 square units
