The area of rectangle is : 2106.0
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
27 square inches
1,080 in.2Hope it helped!
3 x 9
To find the area of a rectangle, you multiply the length by the width. In this case, the length is 9 units and the width is 3 units. Therefore, the area of the rectangle would be 9 x 3 = 27 square units.
If it has an area of 81 square units it could be 1 unit x 81 units giving a perimeter of 2 x (1 + 81) = 164 units;It could be 3 units by 27 units giving a perimeter of 2 x (3 + 27) = 60 units;There are many other possibilities, most with non-whole number lengths of the sides.
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
27:55
To find the area of a rectangle, you multiply its length by its width. In this case, the length is 9cm and the width is 3cm. So, the area of the rectangle would be 9cm x 3cm = 27 square centimeters.
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
To find the area of a rectangle, you multiply its length by its width. In this case, the rectangle is 3 cm long and 9 cm wide. So, the area would be 3 cm x 9 cm = 27 square cm.
27 square inches
1,080 in.2Hope it helped!
If that's a rectangle, the perimeter is 24 inches and the area is 27 square inches.
3 x 9
To find the possible dimensions of a rectangle with an area of 54, we can consider pairs of factors of 54. The factor pairs are (1, 54), (2, 27), (3, 18), (6, 9). Therefore, the possible dimensions of the rectangle are: 1 by 54, 2 by 27, 3 by 18, and 6 by 9.