No. Different rectangles, all with the same area, may have a different perimeter. Example:* A rectangle of 4 x 1 has an area of 4 square units, and a perimeter of 2(4+1) = 10. * A rectangle of 2 x 2 has an area of 4 square units, and a perimeter of 2(2+2) = 8. * A rectangle of 8 x 1/2 has an area of 4 square units, and a perimeter of 2(8 + 1/2) = 17. In fact, for any given area, you can make the perimeter arbitrarily large. On the other hand, you get the lowest perimeter if your rectangle is a square.
Not always because a 2 by 12 rectangle will have the same area as a 4 by 6 rectangle but they both will have different perimeters.
It is possible for to shapes to have the same area but different perimeters because, for example, one shape could be a 2 by 4 rectangle and another shape be a 1 by 8 rectangle. Both shapes have an area of 8 (2*4=8 and 1*8=8) but the 2 by 4 has a perimeter of 12 (2+2+4+4=12) but the 1 by 8 rectangle has an area of 18 (1+1+8+8=18).
The area of rectangle is : 100.0
The equation for the area of the rectangle is A = Y2 + 4 Y. A = L * W = (Y + 4) (Y)
Area of a rectangle= length x height.For example:A 2' by 4' rectangle would have an area of 2 x 4 = 8 square feet.As a formula, it is L*W=A.
Rectangle with area 28 m2 and width = 4 m => length = 28/4 = 7m. Then, perimeter = 2*(4+7) = 2*11 = 22 metres.
Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.
Area of square = 4 x 4 = 16 sq ft; area of rectangle = 3 x 2 = 6 sq ft. Area of the square is two-and-two-thirds that of the rectangle.
The area of rectangle is : 12.0
The rectangle would have a width of 2 and a length of 4.
No, a 2 by 4 rectangle is not congruent to a 4 by 8 rectangle. They are similar, but the 4 by 8 rectangle is 4 times bigger than the 2 by 4.
Not at all. For example:A square of 2 x 2 will have a perimeter of 8, and an area of 4. A rectangle of 3 x 1 will also have a perimeter of 8, and an area of 3.A "rectangle" of 4 x 0 will also have a perimeter of 8, but the area has shrunk down to zero. The circle has the largest area for a given perimeter/circumference.
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
Length = 4, Width = 2
8/4 = 2 metres wide
To find an area of a rectangle, take the length and width and multiply the two together. In your case the length is 4, the width is 2, find the product... so 4 x 2 = 8. Thus the area of the rectangle is 8 units squared. It's perimeter is 12, which means 2l x 2w or 2(length) x 2(width) = 2(4) x 2(2) = 12.