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What is the area of a regular octagon that has a perimeter of 100 cm?
Wiki User
∙ 6y ago
The regular octagon will have 8 sides of 12.5 cm and consist of 8 congruent isosceles triangles with equal base angles of 67.5 degrees and an apex angle of 45 degrees.
The sine rule is: a/sinA = b/sinB = c/sinC
Using the sine rule its equal sides are: 16.33203706 cm
Its area is: 0.5*16.33203706^2 *sin(45)*8 = 754.4417382 square cm
Alternatively its area is: 0.5*16.33203706*12.5*sin(67.5)*8 = 754.4417382 square cm
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is approx 754 cm2.
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