124
15 and 4 are the factors of 120 that add up to 19.
The factors that multiply to 120 and add up to -8 are -12 and 10. This is because when you multiply -12 and 10, you get -120, and when you add them together, you get -8. Thus, the pair of factors you are looking for is (-12, 10).
To find eight numbers that have an average of 15, their total sum must be 120 (since 15 multiplied by 8 equals 120). One possible set of numbers could be: 10, 12, 15, 18, 14, 16, 20, and 15. These numbers add up to 120, thus giving an average of 15.
-15+-8=-23 -15*-8=120
How about: 120+1.2 = 121.2
-1, 6 and -12.
146
144. You divide 120 by 5 since 20 is one fifth of 100 percent. You will end up with 24. You then add it to the original number, 120, and you get 144.
No, 3 is a factor of both. Note that the digits of 120 add up to 3 and those of 147 add up to 12. Both are multiples of 3 so the numbers 120 s and 147 are divisible by 3 and not relatively prime
138
120 + 138
154