Equation: x^2 +y^2 -4x -2y -4 = 0
Completing the squares: (x-2)^2 +(y-1)^2 -4-1-4 = 0
So: (x-2)^2 +(y-1)^2 = 9
Therefore the centre of the circle is at (2, 1) and its radius is 3
You need to change the equation to the form (x - a) squared + (y - b) squared = r squared. You do this by completing the square. In this case, (a, b) will be the center of the circle, and r will be the radius.
The centre is (a, a) and the radius is a*sqrt(2).
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
x2+y2-4x-6y-3 = 0 Using the appropriate formula it works out as:- Centre of circle: (2, 3) Radius of circle: 4.
Area equals pi times the radius squared.
area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821
The centre is (a, a) and the radius is a*sqrt(2).
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Area equals pi times the radius squared.
x2+y2-4x-6y-3 = 0 Using the appropriate formula it works out as:- Centre of circle: (2, 3) Radius of circle: 4.
area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821
Pi (3.14) times the radius of a circle squared, equals the circumference of a circle.
If: x^2+y^2 -4x -2y -4 = 0 Then by completing the squares of x and y: (x-2)^2+(y-1)^2 = 9 Therefore the centre of the circle is at (2, 1) and its radius is 3 units
Area of a circle is: pi times radius squared
Area of a circle equals pi (3.14) times the radius squared.
The graph is a circle with a radius of 6, centered at the origin.
A= Area of the circle¶= Pi (About 3.14)r= Radius squared (Radius times radius)3.14 * Radius squared
If 0.8cm is the radius (distance from the centre to the edge of the circle) of the circle, the area of the circle is 2.010619298 cm squared. If 0.8cm is the diameter (distance from one side of the circle to the other), the circle's area is 0.5026548246cm squared.