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Equation: x^2 +y^2 -4x -2y -4 = 0

Completing the squares: (x-2)^2 +(y-1)^2 -4-1-4 = 0

So: (x-2)^2 +(y-1)^2 = 9

Therefore the centre of the circle is at (2, 1) and its radius is 3

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