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What is the coordinate for the vertex of the parabola represented by the equation y equals xsquared -6x subtract 16?
Wiki User
∙ 12y ago
-22
Francesca Feil
Wiki User
∙ 12y agoY = X2 - 6X - 16
set to 0
X2 - 6X - 16 = 0
add 16 to both sides
X2 - 6X = 16
now, halve the coefficient of the linear term (- 6/2 of - 6X ), square it and add it to both sides
X2 - 6X + 9 = 16 + 9
now, gather terms on right and factor on the left of equation
(X - 3)2 = 25
set to 0
(X - 3)2 - 25 = 0
---------------------
(3, - 25)
------------------coordinates of the vertex
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