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The answer to your question is 8 cm diameter, increasing to 16 cm diameter:

r2 squared = 4 x r1 squared and r2 = r1 + 4

r1 squared + 8r1 + 16 = 4r1 squared

3r1 squared - 8r1 - 16 = 0

Factors are (3r1 + 4)(r1 - 4), so original radius was 4cm (area 16pi) and increased radius is 8 cm (area 64pi).

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Q: What is the diameter of a circle whose area is quadrupled when the length of its radius is increased by 4cm?
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