What is the difference between 47 ft- lbs and 47 in-lbs when torquing fasteners?

Answer 1

0

Answer 2

Torque is the amount of force applied multiplied by the distance from the pivot point.

So if you had a wrench and were tightening a bolt, and the wrench handle is 10 inches long, and you applied 4.7 pounds-force (lbf), you would get:

(10 in ) * ( 4.7 lbf) = 47 inch-pounds of torque

So if the handle were 10 feet long (120 inches) with the same force, you would

have 47 foot-pounds of torque.

Since 1 foot is 12 inches, a torque of 47 foot-pounds is 12 times greater than 47 inch-pounds

or 47 foot-pounds = 12 * (47 inch-pounds) = 564 inch-pounds