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What is the equation of a line with coordinates of 3 -4 and is perpendicular to the line of 5x-2y equals 3?
Wiki User
∙ 11y ago
Equation of given line: 5x - 2y = 3
In slope intercept form, that is: 2y = 5x - 3
or y = 5/2*x - 3/2
So gradient of given line = 5/2
Therefore, gradient of perpendicular line = -1/(5/2) = -2/5
Also, the point (3, -4) is on this line
So equation is: y - (-4) = -2/5*(x - 3)
y + 4 = -2/5*(x - 3)
5y - 20 = -2x + 6
2x + 5y = 26
Equation of given line: 5x - 2y = 3
In slope intercept form, that is: 2y = 5x - 3
or y = 5/2*x - 3/2
So gradient of given line = 5/2
Therefore, gradient of perpendicular line = -1/(5/2) = -2/5
Also, the point (3, -4) is on this line
So equation is: y - (-4) = -2/5*(x - 3)
y + 4 = -2/5*(x - 3)
5y - 20 = -2x + 6
2x + 5y = 26
Equation of given line: 5x - 2y = 3
In slope intercept form, that is: 2y = 5x - 3
or y = 5/2*x - 3/2
So gradient of given line = 5/2
Therefore, gradient of perpendicular line = -1/(5/2) = -2/5
Also, the point (3, -4) is on this line
So equation is: y - (-4) = -2/5*(x - 3)
y + 4 = -2/5*(x - 3)
5y - 20 = -2x + 6
2x + 5y = 26
Equation of given line: 5x - 2y = 3
In slope intercept form, that is: 2y = 5x - 3
or y = 5/2*x - 3/2
So gradient of given line = 5/2
Therefore, gradient of perpendicular line = -1/(5/2) = -2/5
Also, the point (3, -4) is on this line
So equation is: y - (-4) = -2/5*(x - 3)
y + 4 = -2/5*(x - 3)
5y - 20 = -2x + 6
2x + 5y = 26
Wiki User
∙ 11y ago
Wiki User
∙ 11y agoEquation of given line: 5x - 2y = 3
In slope intercept form, that is: 2y = 5x - 3
or y = 5/2*x - 3/2
So gradient of given line = 5/2
Therefore, gradient of perpendicular line = -1/(5/2) = -2/5
Also, the point (3, -4) is on this line
So equation is: y - (-4) = -2/5*(x - 3)
y + 4 = -2/5*(x - 3)
5y - 20 = -2x + 6
2x + 5y = 26
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The powers of x in the two terms are different.The powers of x in the two terms are different.The powers of x in the two terms are different.The powers of x in the two terms are different.
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