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If: y = x^2 -10x +13 and y = x^2 -4x +7 Then: x^2 -10x +13 = x^2 -4x +7 Transposing terms: -6x +6 = 0 => -6x = -6 => x = 1 Substituting the value of x into the original equations point of contact is at: (1, 4)
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
530.9291585 squared inches to be exact. * * * * * To be exact? Since when has it been possible to express an exact multiple of pi?
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There is no shift in the PPC.Only a dot is marked within the curve(Not on the curve) in the exact center of the two axes.The shape of the PPC is concave to the origin.
By differentiating the answer and plugging in the x value along the curve, you are finding the exact slope of the curve at that point. In effect, this would be the slope of the tangent line, as a tangent line only intersects another at one point. To find the equation of a tangent line to a curve, use the point slope form (y-y1)=m(x-x1), m being the slope. Use the differential to find the slope and use the point on the curve to plug in for (x1, y1).
There's actually no exact translation for tangent in Tagalog langauge.
If: y = x^2 -10x +13 and y = x^2 -4x +7 Then: x^2 -10x +13 = x^2 -4x +7 Transposing terms: -6x +6 = 0 => -6x = -6 => x = 1 Substituting the value of x into the original equations point of contact is at: (1, 4)
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
The instantaneous speed at a specific point on a speed-time graph is the slope of the tangent to the curve at that point. It represents the speed of an object at that exact moment in time. This can be determined by calculating the gradient at that particular point.
The slope of a line drawn tangent to a point on a position vs. time graph represents the instantaneous velocity of the object at that point. It describes how the position of the object is changing at that exact moment in time.
530.9291585 squared inches to be exact. * * * * * To be exact? Since when has it been possible to express an exact multiple of pi?
Given y=LN(x2). To find the equation of a tangent line to a point on a graph, we must figure out what the slope is at that exact point. We must take the derivitave with respect to x to come up with a function that will give the slope of the tangent line at any point on the graph. Any text book will tell you that the derivative with respect to X of LN(U) is the quantity U prime over U(In other words, the derivitive of U over U. U is whatever is inside the natural log). In this case, it is y = (2x/x2). To find the slope, we then plug in an x coordinate, 1. We get y=2. The slope of the tangent line at this point is 2. We now have m for the slope-intercept form y = mx + b. Now we must find b. B is the y intercept, aka where does the graph intersect the y axis. We use the slope. We know that the graph of the tangent line contains the point (0,1). We go down 2 and left one, to find that the tangent line intercepts the y axis at -1. We now have B. The equation of the tangent line of y = LN(x2) at X = 1 is y = 2X-1. Hope this helps!!!
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44,579,000 km2
Use Guassian quadrature with n=1 and n=2 and compare to exact value I=
The Lorenz curve has a major disadvantage of not showing the distributions exact value. It is also makes it difficult to compare different data sets.