It looks as if each number is equal to the previous number, multiplied by -1/2. Therefore, one way to write the formula for the n'th term is:-24 x (-1/2)^n
It is Un = -24*(-1/2)^n for n = 1, 2, 3, ...
Per the formula in the related link, substitution into the formula yields (3*12)1/2, which is (36)1/2 or 6.
The quadratic formula is.... -b +/- sqrt(b^2 -4ac)/2a in this problem.... ( 3X^2 + 6X + 2 = 0 ) a = 3 b = 6 c = 2 so..... -6 +/- sqrt(6^2 - 4(3)(2))/2(3) -6 +/- sqrt(36 -24)/6 -6 +/- sqrt(12)/6 since square root 12 is irrational -1 +/- sqrt(12) is the answer
12 + (2 x 3) - 7 = 12 + 6 - 7 = 11
x=(6±sqrt(36-4*6))/2 x=3±(sqrt(12)/2) x=3±sqrt(3)
The expression "12 minus 6 divide 3" simplifies to "12 - (6 รท 3)". The division 6 รท 3 equals 2, so the expression simplifies further to "12 - 2". Finally, the subtraction 12 - 2 equals 10. Therefore, the answer to 12 minus 6 divide 3 is 10.
Type yourWhich choice is the explicit formula for the following geometric sequence? answer here...
The answer depends on what the explicit rule is!
Per the formula in the related link, substitution into the formula yields (3*12)1/2, which is (36)1/2 or 6.
Each term is 3 times greater than the previous term and so the next term will be 486
Good Question! After 6 years of math classes in college, and 30+ years of teaching (during which I took many summer classes) I've never seen an explicit formula for the nth term of the Fibonacci sequence. Study more math and maybe you can discover the explicit formula that you want.
12 is the LCM of any of the following 44 sets:{12},{1, 12}, {2, 12}, {3, 4}, {3, 12}, {4, 6} , {4, 12}, {6, 12},{1, 2, 12}, {1, 3, 4}, {1, 3, 12}, {1, 4, 6}, {1, 4, 12},{1, 6, 12}, {2, 3, 4}, {2, 3, 12}, {2, 4, 6}, {2, 4, 12},{2, 6, 12}, {3, 4, 6}, {3, 4, 12}, {3, 6, 12}, {4, 6, 12},{1, 2, 3, 12}, {1, 2, 4, 12}, {1, 2, 6, 12}, {1, 3, 4, 12},{1, 3, 6, 12}, {1, 4, 6, 12}, {1, 2, 4, 6}, {1, 3, 4, 6},{1, 2, 3, 4}, {2, 3, 4, 6}, {2, 3, 4, 12}, {2, 3, 6, 12},{2, 4, 6, 12}, {3, 4, 6, 12},{1, 2, 3, 4, 6}, {1, 2, 3, 4, 12}, {1, 2, 3, 6, 12},{1, 2, 4, 6, 12}, {1, 3, 4, 6, 12}, {2, 3, 4, 6, 12},{1, 2, 3, 4, 6, 12}.
The quadratic formula is.... -b +/- sqrt(b^2 -4ac)/2a in this problem.... ( 3X^2 + 6X + 2 = 0 ) a = 3 b = 6 c = 2 so..... -6 +/- sqrt(6^2 - 4(3)(2))/2(3) -6 +/- sqrt(36 -24)/6 -6 +/- sqrt(12)/6 since square root 12 is irrational -1 +/- sqrt(12) is the answer
12 + (2 x 3) - 7 = 12 + 6 - 7 = 11
In the formula C6H12O6, there are 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
x=(6±sqrt(36-4*6))/2 x=3±(sqrt(12)/2) x=3±sqrt(3)
(6/3)/12 = 2/12 = 1/6 or 6/(3/12) = 6/(1/4) = 24
12, 6, 0, -6, ...