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Q: What is the integral of 1 divided by the square root of the quantity of the square of x minus 1 with respect to x?

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âˆ« f'(x)/âˆš(af(x) + b) dx = 2âˆš(af(x) + b)/a + C C is the constant of integration.

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âˆ« f'(x)/âˆš[f(x)2 + a] dx = ln[f(x) + âˆš(f(x)2 + a)] + C C is the constant of integration.

âˆ« 1/sinh2(x) dx = -cotanh + C C is the constant of integration.

âˆ« 1/cosh2(x) dx = tanh(x) + C C is the constant of integration.

âˆ« f'(x)/[f(x)âˆš(f(x)2 - a2)] dx = (1/a)arcses(f(x)/a) + C C is the constant of integration.

âˆ« f'(x)/âˆš(a2 - f(x)2) dx = arcsin(f(x)/a) + C C is the constant of integration.

replace square root o x with t.

âˆ« f'(x)/(af(x)2 + bf) dx = (1/b)ln[f(x)/(af(x) + b)] + C C is the constant of integration.

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