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What is the largest angle in and area of a triangle with sides of 14 cm by 9 cm by 8.5 cm?
Wiki User
∙ 6y ago
Using the cosine rule the angle can be found:
Largest angle is opposite largest side
→ A = arc cos ((14² - 9² - 8.5²)/(2 × 9 × 8.5)) ≈ 73.8°
For the area, use Heron's formula
Let S = half the perimeter = ½(14 + 9 + 8.5) = 15.75
Area = √(s(s - a)(s - b)(s - c))
= √(15.75 × (15.75 - 14) × (15.75 - 9) × (15.75 - 8.5))
≈ 36.73 sq cm.
Alternatively, you can use the Sine ratio on the largest angle and the two shorter sides:
area ≈ ½ × 9 × 8.5 × sin 73.8 ≈ 36.73 sq cm
Another Answer: The largest angle of the triangle is 106.23 degrees and its area is 36.73 square cm both rounded to two decimal places
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoAnother Answer: Largest angle of the triangle is 106.23 degrees and its area is 36.73 square cm both rounded to two decimal places
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What is the largest angle and area of a triangle that has sides of 14cm by 8.5cm by 9cm?
Using the cosine rule the largest angle = 106.23 degrees to two decimal places Area: 0.5*9*8.5*sin(106.23) = 36.73 square cm to two decimal places
What is the area of a triangle with sides of 36 39 and 15?
It is a right angle triangle with an hypotenuse of 39 and sides of 36 and 15. Area of triangle is 0.5*36*15 = 270 square units
How do you fine the area of a triangle using sine?
Given two sides and the angle between them, you can use the formula: Area = 1/2*a*b*sinѲ Where a and b are the sides, and Ѳ the angle between them.
How do you find an area of an isosceles triangle?
It depends on what information you have: one side and an angle, two different sides.
How do you find the area of a right angle triangle with all sides given?
(base x height) / 2
What is the largest angle and area of a triangle having sides of 14cm by 8.5cm by 9cm?
Using cosine rule largest angle is 106.23 degrees to two decimal places. Area of triangle: 0.5*8.5*9*sin(106.23) = 36.73 square cm to two decimal places.
What is the largest angle and area of a triangle with sides of 14mm by 8.5mm by 9mm?
Using cosine rule largest angle is: 106.23 degrees Using area formula: 0.5*9*8.5*sin(106.23) = 36.726 square mm
What is the largest angle and area of a triangle that has sides of 14cm by 8.5cm by 9cm?
Using the cosine rule the largest angle = 106.23 degrees to two decimal places Area: 0.5*9*8.5*sin(106.23) = 36.73 square cm to two decimal places
What is the area of a triangle with sides of 36 39 and 15?
It is a right angle triangle with an hypotenuse of 39 and sides of 36 and 15. Area of triangle is 0.5*36*15 = 270 square units
What are the two formulas for the area of a triangle?
The basic formula is: A = 1/2bh where A is area, b is the base of the triangle and h is the height Using trigonometry, the area of a triangle can also be expressed as: A = 1/2absinC, where A is the area, a and b are two sides of the triangle, and C is the angle between those sides.
How do you fine the area of a triangle using sine?
Given two sides and the angle between them, you can use the formula: Area = 1/2*a*b*sinѲ Where a and b are the sides, and Ѳ the angle between them.
How do you find an area of an isosceles triangle?
It depends on what information you have: one side and an angle, two different sides.
How do you find the area of a right angle triangle with all sides given?
(base x height) / 2
What is the largest angle and area of a triangle with sides of 14 cm 9 cm and 8.5 cm?
The largest angle will be opposite the longest side which is 14 cm and by using the cosine rule it works out as 106.23 degrees rounded to two decimal places and its area is 0.5*9*8.5*sin(106.23) = 36.726 square cm to three decimal places.
Oblique triangle given two sides and an angles opposite one of th em?
"Two sides and the angle opposite one of them" doesn't uniquely define a triangle. That is,there can be two or more triangles with different size, or shape, or area that have the sametwo sides and the same angle opposite one of them.In order to use two sides to define a unique triangle, you also have to give the angle between them.
How are you going to solve for the area of an isosceles triangle if the only given is the sides?
To find the area of a triangle you use A=0.5abSin(C) with a and b being two sides next to each other and C being the angle between them. Because you have 3 sides you can use the cosine rule, which is Cos(C)= (a2 + b2 - c2) /2a This finds the angle you need. But make sure you use C and c as the angle and the side opposite each other. Then put this angle into the area of a triangle rule as above.
How do you find the area of a triangle when given 3 angles and the perimeter?
If you know the lengths of 2 sides and the included angle then use: Area of a triangle = 1/2*a*b*sinC
