In order of magnitude (size), your list is:110,111,111,210,210,210therefore, the median (middle) value is (111+210)/2 = 160.5
You can calculate the mode, mean and median of any set of integers.
36, 37 and 38.
put them in order and the middle one is the median
110 + 111 + 112 = 333
In order of magnitude (size), your list is:110,111,111,210,210,210therefore, the median (middle) value is (111+210)/2 = 160.5
1006.
Just multiply 111 by different integers (whole numbers). 111, 222, 333 and so on.
If your question is: How many integers are there form 17 to 111, INCLUDING 17 and 111.", then I can help you there. Subtract 111-17 and your result will always be: 94. But since the question states that you need to find it Including 17 and 111 then you add one. Which is 95. You're welcome!
You can calculate the mode, mean and median of any set of integers.
36, 37 and 38.
Think of 5 positive integers that have a mode of 4 and 6, a median of 6 and a mean of 7.
put them in order and the middle one is the median
The median is the middle number when they have been put into order (or the mean average of the middle 2 numbers when there are an even amount of numbers).In this question we have six numbers (an even amount). The median is therefore going to be the mean average of the middle two numbers. These numbers are 71 & 111 and so the answer is:(71 + 111) / 2 = 182/2 = 91
The numbers are 111, 113 and 115.
110 + 111 + 112 = 333
X + (X+1) = 111; 2X + 1 = 111; 2X = 110; X = 55 and the other number is 56