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There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.
The answer depends on where the missing number is located.
First (before the 2): 45
Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24
Second (between 2 and 4): 6.6
Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60
Third (between 4 and 9): 9.3
Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120
and so on.
There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.
The answer depends on where the missing number is located.
First (before the 2): 45
Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24
Second (between 2 and 4): 6.6
Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60
Third (between 4 and 9): 9.3
Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120
and so on.
There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.
The answer depends on where the missing number is located.
First (before the 2): 45
Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24
Second (between 2 and 4): 6.6
Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60
Third (between 4 and 9): 9.3
Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120
and so on.
There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.
The answer depends on where the missing number is located.
First (before the 2): 45
Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24
Second (between 2 and 4): 6.6
Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60
Third (between 4 and 9): 9.3
Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120
and so on.
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RossThere are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.
The answer depends on where the missing number is located.
First (before the 2): 45
Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24
Second (between 2 and 4): 6.6
Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60
Third (between 4 and 9): 9.3
Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120
and so on.
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What is the missing number in the sequence 1 9 28 - 126 217?
65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217
What number corresponds to the sequence in which Texas was admitted?
28
What number completes this sequence 100 52 28 16 10?
A sequence never ends. The next number in this one is 7 .
What is missing number in sequence 2-4-10-82-244?
There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.Furthermore, the answer depends on where, in the given sequence, the missing number is meant to be.
What is the number 42 of 150?
The number 42 is the 42nd number in a sequence of 150 numbers.
