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There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.

More answers

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.

Q: What is the missing number in the sequence 2 4 9 28 125?

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65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217

28

A sequence never ends. The next number in this one is 7 .

There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.Furthermore, the answer depends on where, in the given sequence, the missing number is meant to be.

The number 42 is the 42nd number in a sequence of 150 numbers.

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65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217

35 is 125% of what:= 35 / 125= 35 / 1.25= 28

28 is the non-cubic number The others work out like this - 2x2x2=8 4x4x4=64 5x5x5=125

28

28% of 125= 28% * 125= 0.28 * 125= 35

A sequence never ends. The next number in this one is 7 .

There are infinitely many polynomials of order 5 that will give these as the first five numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.Furthermore, the answer depends on where, in the given sequence, the missing number is meant to be.

In this sequence, it should be 27, not 28 (28 is not divisible by 3)

The number 42 is the 42nd number in a sequence of 150 numbers.

A single number, such as 4642142824816 does not constitute a sequence.

-100

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