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# What is the missing number in the sequence 2 4 9 28 125?

Updated: 9/23/2023 Wiki User

10y ago

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on. Wiki User

10y ago   Wiki User

10y ago

There are infinitely many functions (rules) that can be found so that they generate the above 5 numbers. A set of coefficients can be found for any polynomial of degree 4 or above that will do the trick. There are also other functional forms that will work.

The answer depends on where the missing number is located.

First (before the 2): 45

Un = (53n4 - 698n3 + 3403n2 - 7150n + 5472)/24

Second (between 2 and 4): 6.6

Un = (111n4 - 1358n3 + 5949n2 - 10522n + 5940)/60

Third (between 4 and 9): 9.3

Un = (169n4 - 1868n3 + 7181n2 - 10762n + 5520)/120

and so on.   Earn +20 pts  