Any two number that you choose can be next. It is easy to find a rule based on a polynomial of order 5 such that the first four numbers are as listed in the question followed by your chosen numbers in the next two places. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
With this sequence, for example, the next two numbers could be -2583 and -7168. These are based on the rule:
U(n) = (-875*n^3 + 5775*n^2 - 11410*n + 6552)/6 for n = 1, 2, 3, ...
The above answer is mathematically valid and cannot be faulted. However, I suggest that the answer that is sought is 1792 and -7168.
0.8929
1 and 112 2 and 56 4 and 28 7 and 16 8 and 14 112 and 1 0.5 and 224 0.25 and 448 0.1 and 1120
The answer is 112. To calculate: 25/100*448 (25 divided by 100 multiplied by 448)
The LCM is: 448
The total number of multiples is infinite. Here are the first 10: 112, 224, 336, 448, 560, 672, 784, 896, 1008, 1120 . . .
Exactly 112 times
0.8929
1 and 112 2 and 56 4 and 28 7 and 16 8 and 14 112 and 1 0.5 and 224 0.25 and 448 0.1 and 1120
The answer is 112. To calculate: 25/100*448 (25 divided by 100 multiplied by 448)
112, 224, 336, 448 +112 . . .
112, 224, 336, 448, 560.
The LCM is: 448
112 times
There can be many answers. 2 x 224 = 448 112 x 4 = 448 44.8 x 10 = 448 4.48 x 100 = 448 etc.
1, 2, 4, 7, 8, 14, 16, 28, 32, 56, 64, 112, 224, 448
112, 224, 336, 448, 560, 672, 794, 916, 1038, 1160, 1272, 1384
1, 2, 4, 7, 8, 14, 16, 28, 32, 56, 64, 112, 224, 448