What is the percent composition for (NH4)2S?

Answer 1

To find the percent composition of (NH4)2S, you first need to calculate the molar mass of the compound. The molar mass of (NH4)2S can be calculated as follows: (1 nitrogen atom * 14.01 g/mol) + (8 hydrogen atoms * 1.01 g/mol) + (1 sulfur atom * 32.06 g/mol) = 68.15 g/mol. Next, you can find the percent composition of each element by dividing the individual element's molar mass by the molar mass of the entire compound and multiplying by 100. The percent composition of (NH4)2S is approximately 20.56% nitrogen, 6.96% hydrogen, and 72.48% sulfur.

Answer 2

The percent composition for (NH4)2S is:
Nitrogen: 41,18 %
Hydrogen: 11,76 %
Sulfur: 47,06 %

Answer 3

2N = 28 g
8H = 8 g
1S = 32 g
Total mass = 68 g
% N = 28/68 = 0.4117 = 41.17% nitrogen
% H = 0.1176 = 11.76% hydrogen
% S = 0.4706 = 47.06% sulfur

Answer 4

41% nitrogen, 12% hydrogen, 47% sulfur.