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Is sodium nitrate or sodium chloride more soluble?
Sodium nitrate (NaNO3) is more soluble in water compared to sodium chloride (NaCl). Sodium nitrate has a higher solubility due to the presence of more polar nitrate (NO3-) ions in the compound.
What is the percent of nitrogen in sodium nitrate?
The percent of nitrogen in sodium nitrate is 16,47 %.
What elements contain sodium nitrate?
NaNO3 -Sodium -Nitrogen -Oxygen
Can you change potassium nitrate into sodium nitrate?
No, it is not possible to directly change potassium nitrate into sodium nitrate. These are two different compounds with different chemical compositions and properties. To obtain sodium nitrate from potassium nitrate, you would need to first separate the potassium and then introduce sodium in a separate chemical reaction.
What is the difference between solubility of sodium nitrate and ammonia?
Sodium nitrate is more soluble in water.
What is the percentage of oxygen in sodium nitrate(NaNO3)?
The percentage of oxygen in sodium nitrate (NaNO3) is 53.9%. This is calculated by dividing the molar mass of oxygen in the compound by the molar mass of the entire compound and then multiplying by 100.
What is the molecular mass of sodium nitrate?
The molecular mass of sodium nitrate (NaNO3) is approximately 85 grams per mole.
What is the percentage by mass of nitrogen in sodium nitrate?
The formula for sodium nitrate is NaNO3, showing that each formula unit contains one sodium atom, one nitrogen atom, and three oxygen atoms. The gram atomic masses of sodium, nitrogen, and oxygen are 22.9898, 14.0067, and 15.9994 respectively. Therefore, the percentage by mass of nitrogen in the compound is: 100{14.0067/[14.0067 + 22.9898 + 3(15.9994)]} or about 16.4795, to the justified number of significant digits.
What is the mass of sodium nitrate at 20 degree Celsius when ya solubility is 880?
The solubility of sodium nitrate at 20°C is 88 g/100 g water. To find the mass of sodium nitrate that can dissolve in water at this temperature, you would need to provide the amount of water in the solution. The mass of sodium nitrate that can dissolve would depend on the total mass of the solution.
What percentage by mass of nitrogen is in aluminum nitrate?
The molar mass of aluminum nitrate (Al(NO3)3) is 213 g/mol. The molar mass of nitrogen in the compound is 14 g/mol. Therefore, the percentage by mass of nitrogen in aluminum nitrate is (3 * 14) / 213 * 100 ≈ 19.7%.
To determine the percentage of sodium chloride in contaminated sodium nitrate?
It is necessary to determine the concentrations of sodium and chlorine using analytical chemistry methods or to determine gravimetrically NaCl with silver nitrate.
What is the mass of 6.0 moles of sodium nitrate (NaNO3)?
To find the mass of 6.0 moles of sodium nitrate (NaNO3), you first need to calculate the molar mass of NaNO3, which is 85.00 g/mol. Then, you multiply the molar mass by the number of moles: 85.00 g/mol x 6.0 mol = 510.0 g. Therefore, the mass of 6.0 moles of sodium nitrate is 510.0 grams.
What is the percentage by mass of nitrogen in ammonium nitrate?
The percentage by mass of nitrogen in ammonium nitrate is 35.0%.
What is the mass of Sodium nitrate that will dissolve in 250g of water at 30 Celsius?
The solubility of sodium nitrate in water at 30 degrees Celsius is approximately 180g per 100g of water. Therefore, in 250g of water, approximately 450g of sodium nitrate can dissolve.
What is the percentage by mass of sodium (Na) in a formula unit of sodium hydrogen carbonate NaHCO3?
The percentage by mass of sodium (Na) in a formula unit of sodium hydrogen carbonate (NaHCO3) is 27,38 %.
What is the percentage of nitrogen by mass in calcium nitrate?
The molar mass of calcium nitrate is 164.1 g/mol. The molar mass of nitrogen is 14.01 g/mol. So, the percentage of nitrogen in calcium nitrate is (14.01 g/mol / 164.1 g/mol) * 100% ≈ 8.54%.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound?
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
