Let the diagonals be x and y:-
If: x+y = 24.5 then y = 24.5-x
If: 0.5xy = 73.7 then 0.5x(24.5-x) = 73.5
So: 24.5x -x^2 -147 = 0
Solving the quadratic equation: x = 14 or x = 10.5
The rhombus will then consist of 4 right angle triangles of base 5.25 and height 7
Using Pythagoras: 5.25^2+7^2 = 76.5625 and its square root is 8.75
Therefore the perimeter of the rhombus: 4*8.75 = 35 cm
Suppose the diagonals are of length 2a and 2bthen sum of diagonals = 2*a + 2*b = 24.5 = 49/2 => a + b = 49/4
Also, area = 2*a*b = 73.5 = 147/2
Suppose the side of the rhombus is c. Then
c^2 = a^2 + b^2 = (a + b)^2 - 2*a*b = (49/4)^2 - 147/2 = 1225/16
=> c = 35/4
Then, perimeter = 4*c = (35/4)*4 = 35 cm
noNo, the diagonals of a rhombus are perpendicular to each other.Unless the rhombus is regular (and called a square) the diagonals are of different lengths.
The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2
Each side S = square root ( 152 + 202 ) = 25The perimeter will then be 4 x S = 100
No. If they were equal the rhombus would become a square.
Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.
Area of the rhombus: 0.5*7.5*10 = 37.5 square cm Perimeter using Pythagoras: 4*square root of (3.75^2 plus 5^2) = 25 cm
No. The diagonals of a rhombus are perpendicular only if the rhombus is a square.
noNo, the diagonals of a rhombus are perpendicular to each other.Unless the rhombus is regular (and called a square) the diagonals are of different lengths.
The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2
If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.
Each side S = square root ( 152 + 202 ) = 25The perimeter will then be 4 x S = 100
Square, rhombus or a kite.
No. If they were equal the rhombus would become a square.
Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.
Perimeter: 4 times square root of (3.5^2+6^2) = 2 times square root of 193 in cm
Rhombus and Square (since a square is just a "special" rhombus, with right angles)
Yes, if they are a square.