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Combine the equations together and using the quadratic equation formula it works out that the point of contact is at (5/8, 5/2)

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6y ago
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6y ago

The coordinates of the point are (0.625, 2.5).

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Q: What is the point of contact when the line y equals 2x plus 1.25 touches the curve y squared equals 10x?
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Related questions

What is the value of k when y equals 3x plus 1 is a line tangent to the curve of x squared plus y squared equals k hence finding the point of contact of the line to the curve?

It is (-0.3, 0.1)


Where is the point of contact when the line y equals 2x plus 1.25 touches the curve y squared equals 10x?

If y = 2x +10 and y^2 = 10x then by forming a single quadratic equation and solving it the point of contact is made at (5/8, 5/2)


What is the point of contact when the tangent line y equals x plus c touches the curve y equals 3x -x -5x squared?

-2


Where are the points of contact when the line 3x -y equals 5 passes through the curve 2x squared plus y squared equals 129?

It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)


What is the point of cotact when the line y equals 2x plus 5 over 4 meets the curve y squared equals 10xa?

If you mean a line of y = 2x+5/4 and a curve of y^2 = 10x Then it works out that the line touches the curve at: (5/8, 5/2)


What is the value of c when y equals x plus c is a tangent to the curve y equals 3 -x -5x squared hence finding the point of contact of the line with the curve showing work?

-2


What is the exact point of contact when the curve of y equals x squared -10x plus 13 touches the curve of y equals x squared -4x plus 7 showing work?

If: y = x^2 -10x +13 and y = x^2 -4x +7 Then: x^2 -10x +13 = x^2 -4x +7 Transposing terms: -6x +6 = 0 => -6x = -6 => x = 1 Substituting the value of x into the original equations point of contact is at: (1, 4)


What is meant by tangent to a curve at a point?

It is a straight line that touches the curve such that the line is perpendicular to the radius of the curve at the point of contact.


At what point is the line of y equals x -4 tangent to the curve of x squared plus y squared equals 8?

(2, -2)


What is the value of k when y equals 3x plus 1 and is a line tangent to the curve of x squared plus y squared equals k?

k = 0.1


What is the definition of a tangent line?

A tangent is a line that just touches a curve at a single point and its gradient equals the rate of change of the curve at that point.


What are the points of contact between the line 3x -2y equals 1 and the curve 3x squared -2y squared plus 5 equals 0?

Equations: 3x-2y = 1 and 3x^2 -2y^2 +5 = 0 By combining the equations into one single quadratic equation and solving it the points of contact are made at (3, 4) and (-1, -2)