Q: What is the probability of flipping a coin and getting tails and than rolling a number greater than two on a number cube?

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The probability of rolling a 2 on a die before flipping a heads on a coin is 1 in 12. The probability of rolling a 2 is 1 in 6. The probability of flipping heads is 1 in 2. Since these are sequentially unrelated events, you simply multiply the probabilities together.

The probability is 5/6 (83.333%).

You take the probability of each event and multiply them. In the case of the given example, your odds or flipping a head and rolling a 5 would be 1/2 * 1/6, which equals 1/12.

50% or 3 out of 6.

1/3

Related questions

It is 0.25

The probability of flipping a quarter and getting heads is 1 in 2. the probability of rolling a die and getting 6 is 1 in 6.

1 in 2.

probability of rolling a 3 = 1/6 probability of flipping a head = 1/2 therefore, overall = 1/12

The probability of rolling a 2 on a die before flipping a heads on a coin is 1 in 12. The probability of rolling a 2 is 1 in 6. The probability of flipping heads is 1 in 2. Since these are sequentially unrelated events, you simply multiply the probabilities together.

The probability of flipping tails on a perfect coin in a perfect toss is 0.5. The probability of rolling 1 on a die is 1 in 6. Likewise, the probability of rolling 6 on a die is 1 in 6. So the probability of rolling either 1 or 6 is 2 in 6 (which is 1 in 3).

the probability is 2/6

The probability is 5/6 (83.333%).

1/24

The probability of rolling a number greater than 6 on a die is 0.

You take the probability of each event and multiply them. In the case of the given example, your odds or flipping a head and rolling a 5 would be 1/2 * 1/6, which equals 1/12.

The probability of rolling any number on a cube can be represented by the formula: X / the number of variables. Since any cube has 6 sides, the probability of rolling any of the numbers 1 through 6 on the cube, can be represented by the formula: X = 1 / 6 = 16.66% The odds or probability of flipping a coin and landing it on either side can be represented by X = the requested result / the number of variables = 1 /2 = 50% Therefore, given the two questions of probability, there is a much greater chance of landing a coin on "tails" rather than rolling a "4".