There is insufficient information in the question to properly answer it. You did not specify how many places and how many 3's there are on the spinner, and you did not specify the set from which you could pick an "a", both of which are necessary pieces of information to calculate probability. Please restate the question.
Spinners have different numbers of sides. Moreover, the sides are not necessarily all equal nor that they are numbered in any particular fashion. The answer depends on these factor. They have not been specified and so the question cannot be answered.
The probability is 2/15.
They are both measures of probability.
Two out of nine. 2:9.
The probability of drawing two blue cards froma box with 3 blue cards and 3 white cards, with replacement, is 1 in 4, or 0.25.The probability of drawing one blue card is 0.5, so the probability of drawing two is 0.5 squared, or 0.25.
There is insufficient information in the question to properly answer it. You did not specify how many places and how many 3's there are on the spinner, and you did not specify the set from which you could pick an "a", both of which are necessary pieces of information to calculate probability. Please restate the question.
Spinners have different numbers of sides. Moreover, the sides are not necessarily all equal nor that they are numbered in any particular fashion. The answer depends on these factor. They have not been specified and so the question cannot be answered.
The probability is 2/15.
They are both measures of probability.
Two out of nine. 2:9.
3/8
First you have 3 blues out of 13 cards, so the first card has probability 3/13. Then you have 2 blues out of 12 cards, so the second card has probability 2/12 or 1/6. The probability of both being blue is the product of these probabilities: P(two blues) = P(first blue) * P(second blue) = (3/13) * (1/6) = 3/78 or 1/26
it is 6/9 simplifyyou get 2/3.
Assuming each possible number on a spinner has the same probability and an unbiased die is being rolled, the answer depends on how many numbers are on the spinner, and how many times the number 4 appears on each.To find the probability, workout the probability of spinning a 4 on the spinner and the probability of rolling a 4 on the die; then as spinning the spinner has no effect on rolling the die, they are independent events and to get the probability of both happening multiply them together.The probability of success is the number of successful outcomes divided by the total number of outcomes, giving:Probability(spinning a 4) = how_many_4s_are_on_the_spinner / how_many_numbers_are_on_the_spinnerProbability(rolling a 4) = how_many_4s_are_on_the_die / how_many_numbers_are_on_the_dieProbability(spinning a 4 and rolling a 4) = Probability(spinning a 4) × Probability(rolling a 4)Examples:an octagonal spinner with the numbers 1-4 on it each twice and a tetrahedral die (as used in D&D games) with the numbers 1-4 on it→ pr(spin 4 & roll 4) = 2/8 × 1/4 = 1/16a decagonal spinner with the numbers 0-9 and a tetrahedral die with the numbers 0-3 on it→ pr(spin 4 & roll 4) = 1/10 × 0/4 = 0a decagonal spinner with the numbers 0-9 and a standard die with the numbers 1-6 on it→ pr(spin 4 & roll 4) = 1/10 × 1/6 =1/60
That probability is the product of the probabilities of the two individual events; for example, if event A has a probability of 50% and event B has a probability of 10%, the probability that both events will happen is 50% x 10% = 5%.
The probability that he will not win both games is 0.58