Assuming you mean probabilities of 0.25 and 0.47, multiply them together to get the combined probabilities.This assumes that the probabilities are independent of one another. This is not always the case in real life; for example, if the company only has one open position, the probability of both being selected would be ZERO.
The browser used for posting questions on this site is totally rubbish because it does not accept most mathematical symbols - even the most basic ones. The chance of Bruce getting selected appears as "25". It is not clear whether this is meant to be .25 or 2/5.
The probability is 1 in 6 as there are 6 sides on a dice and an even chance of each side being selected.
48/52 or 92% chance of NOT getting an ace.
5/6 There is a 5 in 6 chance of not getting a 6.
obviously it is a 50-50 chance
There is a one out of six chance.
In probability sampling,every item in the population has a known chance of being selected as a member.In non-probability sampling, the probability that any item in the population will be selected for a sample cannot be determined.
0 chance
A 1/13 Chance (Probability).
The probability is 1 in 6 as there are 6 sides on a dice and an even chance of each side being selected.
50% chance.
Probability = 0.5
If you mean what is the probability of getting a heads/tails, it is a 1 in 2 chance (50/50 chance). You are just as likely to get a heads as you are to get a tails.
Simple random sampling.
48/52 or 92% chance of NOT getting an ace.
5/6 There is a 5 in 6 chance of not getting a 6.
you have a 1/13 chance of getting an ace in a pack of cards
Getting admission in IP with this rank might not be easy.Since the seats are selected, you have 50% chances of getting selected