0.028
3.5667
To find a three-digit number that when divided by 7 gives a remainder of 3 and when divided by 8 also gives a remainder of 3, we can express this mathematically. The number can be written as ( n = 7k + 3 ) for some integer ( k ), and it also needs to satisfy ( n \equiv 3 \mod 8 ). Testing three-digit numbers that meet these conditions, we find that 107 is one such number, as it satisfies both ( 107 \div 7 = 15) remainder 2 and ( 107 \div 8 = 13) remainder 3.
26.75
107
The process of multiplication doesn't produce remainders.The process of division does.If you want to divide a 3-digit number by a one-digit numberand get a remainder of 8, try these:107 divided by 9116 divided by 9125 divided by 9134 divided by 9143 divided by 9..Add as many 9s to 107 as you want to, and then divide the result by 9.The remainder will always be 8.
26.75
3.5667
107
7.6429
107.6923
26.75
107
The process of multiplication doesn't produce remainders.The process of division does.If you want to divide a 3-digit number by a one-digit numberand get a remainder of 8, try these:107 divided by 9116 divided by 9125 divided by 9134 divided by 9143 divided by 9..Add as many 9s to 107 as you want to, and then divide the result by 9.The remainder will always be 8.
107 divided by 12 equals 8 with a remainder of 11. There are many other possible solutions as well.
58
59
29