Best Answer

There are infinitely many rules that contain the point (1,5), eg:

y = 5x

y = 4x + 1

y = 3x + 2

y = x² + 3

y = 3x³ + 2x²

y = 4x³ + 3x² - 2x

More answers

Lvl 2

See closely its by 5 but far and backwards its 7-4 !!🌷

Q: What is the rule for 1 on the x axis and for 5 on the y axis?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

Twice at 1 and 5/2 2x2-7x+5 = 0 (2x-5)(x-1) = 0 x = 1 or x = 5/2

If you mean: 3x2+8+5 = 0 Then it crosses the x axis at points -1 and -5/3

5 units, x axis

y=1 does not cross the x-axis. It is a line parallel to the x-axis (and therefore can't ever cross it)

Start at (0, 1 [x, y]). Then, when you go right, for every 1 on the x axis, the line increases 2 on the y axis. The next point would be (1, 3), then (2, 5), then (3, 7), then (4, 9). Going the other way (to the negatives), you would subtract 2 on the y axis for each 1 on the x axis. The points would be (-1, -1), (-2, -3), (-3, -5), and so on.

Related questions

(x,y) --> (x,-y)

Twice at 1 and 5/2 2x2-7x+5 = 0 (2x-5)(x-1) = 0 x = 1 or x = 5/2

If you mean: 3x2+8+5 = 0 Then it crosses the x axis at points -1 and -5/3

(x' , y') = (-x + 1 , y + 4)

-1

5 units, x axis

The area under a curve (between it and the x-axis) is found by integrating the curve: area = ∫ y dx The area enclosed between the curve and the x-axis is bounded by where the curve meets the x-axis. 7x - x² - 10 = -(x - 2)(x - 5) = 0 → The curve meets the x-axis at x = 2 and x = 5 The area between the limits is the difference between the value of the the integral at the limits. → A = ∫ y dx = ∫ 7x - x² - 10 dx = (7/2)x² - (1/3)x³ - 10x + c → A = ((7/2)×5² - (1/3)×5³ - 10×5 + c) - ((7/2)×2² - (1/3)×2³ - 10×2 + c) = 4.5

Equation of circle: x^2 +y^2 -2x -6y +5 = 0 Completing the squares: (x-1)^2 +(y-3)^2 = 5 Center of circle: (1, 3) Tangent line from (3, 4) meets the x axis at: (5, 0) Distance from (5, 0) to (1, 3) = 5 using the distance formula

By taking a coordinate system with origin at the center of the ellipse, and x-axis along the major axis, and y-axis along the minor axis, then the ellipse intercepts the x-axis at -5 and 5, and the y-axis at -2 and 2. So that the equation of the ellipse x2/a2 + y2/b2 = 1 becomes x2/52 + y2/22 = 1 or x2/25 + y2/4 = 1.

f(x, y) = (x, -y)

y=1 does not cross the x-axis. It is a line parallel to the x-axis (and therefore can't ever cross it)

your equation y=3x-5 is a line. this line crosses the y-axis at -5 and the x-axis at 5/3. the slope is 3/1