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RossAlthough your angle unit isn't stated, we assume you're talking radians, just because
your angle has a "pi" in it ... not much to go on, but hey! , we routinely do even more
with even less here at WikiAnswers.
Sin (19 pi / 6 radians) = -0.5
Sin (19 pi / 6 degrees) = 0.17276 (rounded)
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What is the sin of pi divided by 6?
1/2
What is the sin of negative pi divided by 6?
Negative 0.5 is.
What is sin pie divided by six equals one half?
Sin(pi/6) = 1/2 is a true statement [not pie].
What is 55 times sin43 divided by sin 23?
55 × sin 43 ÷ sin 23 ≈ 96
What is the sin of pi divided by 2?
Do you mean Sin(pi/2) = 1 or [Sin(pi)] /2 = 0.0274....
What is the sin of pi divided by 6?
1/2
What is the sin of negative pi divided by 6?
Negative 0.5 is.
If sin y and deg a divided by 6 and tan y and deg a divided by b what is the value of cos y and deg (6 points)?
1
What is sin pie divided by six equals one half?
Sin(pi/6) = 1/2 is a true statement [not pie].
What is 55 times sin43 divided by sin 23?
55 × sin 43 ÷ sin 23 ≈ 96
What is the sin of pi divided by 2?
Do you mean Sin(pi/2) = 1 or [Sin(pi)] /2 = 0.0274....
Verify that sin minus cos plus 1 divided by sin plus cos subtract 1 equals sin plus 1 divided by cos?
[sin - cos + 1]/[sin + cos - 1] = [sin + 1]/cosiff [sin - cos + 1]*cos = [sin + 1]*[sin + cos - 1]iff sin*cos - cos^2 + cos = sin^2 + sin*cos - sin + sin + cos - 1iff -cos^2 = sin^2 - 11 = sin^2 + cos^2, which is true,
What is the derivative of 6 sin x mutiply sin x?
(6 Cosx)2
What is the exact value of sin 405?
sin(405) = square root of 2 divided by 2 which is about 0.7071067812
How do you prove that 2 sin 3x divided by sin x plus 2 cos 3x divided by cos x equals 8 cos 2x?
You need to know the trigonometric formulae for sin and cos of compound angles. sin(x+y) = sin(x)*cos(y)+cos(x)*sin(y) and cos(x+y) = cos(x)*cos(y) - sin(x)*sin(y) Using these, y = x implies that sin(2x) = sin(x+x) = 2*sin(x)cos(x) and cos(2x) = cos(x+x) = cos^2(x) - sin^2(x) Next, the triple angle formulae are: sin(3x) = sin(2x + x) = 3*sin(x) - 4*sin^3(x) and cos(3x) = 4*cos^3(x) - 3*cos(x) Then the left hand side = 2*[3*sin(x) - 4*sin^3(x)]/sin(x) + 2*[4*cos^3(x) - 3*cos(x)]/cos(x) = 6 - 8*sin^2(x) + 8cos^2(x) - 6 = 8*[cos^2(x) - sin^2(x)] = 8*cos(2x) = right hand side.
What is the amplitude for y equals sin x divided by 2?
Assuming the question refers to [sin(x)]/2 rather than sin(x/2) the answer is 1.
What is the derivative of cos x sin x divided by cos x sin x?
(cos x sin x) / (cos x sin x) = 1. The derivative of a constant, such as 1, is zero.
