5x - y = -2
5x = y - 2 (-2 is the offset of the sloping line)
So for every unit up the y-axis, the sloping line's co-ordinate is 5 units to the right on the x-axis. the slope is 1 in 5 or converting to angular dimensions, tan O = 1/5 or O = ?.
This is not right. The slope is 5 if y is plotted upwards as normal. For every increase of 1 in x, y increases by 5.
The slope is 5.
-3
7
If: 2y+5x = 4 Then: y = -2.5x+2 whereas the slope is -2.5 and the y intercept is 2
The slope (m) is -2.5 -2y = 5x-12 -2y/-2 = (5x-12)/-2 y=-2.5x + 6 or more neatly: y= 6-2.5x
The slope is 5.
-3
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
8
7
If: 2y+5x = 4 Then: y = -2.5x+2 whereas the slope is -2.5 and the y intercept is 2
It has the same slope as the line in the question. If a line has equation y = mx + c, its slope is m. If the line in question is y = 5x + 3, the slope of a parallel line is 5; If the line in question is y + 5x = 3 → y = -5x + 3 (subtract 5x from both sides), the slope of a parallel line is -5.
5 and the y intercept is 2
The slope (m) is -2.5 -2y = 5x-12 -2y/-2 = (5x-12)/-2 y=-2.5x + 6 or more neatly: y= 6-2.5x
If you mean: y = 5x-2 then the perpendicular slope is -1/5
You are missing a - or + sign. The answer is 5/2 though. :)
5x-2y=11 -2y=-5x+11 y=(5/2)x - 11/2 Slope is 5/2