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y-2 = -3x ok you need to rewrite this in the form of y = mx+c where m = slope and c = y intercept y = -3x+2 slope = -3 y intercept = 2
Slope=3, y-intercept=0. y=3x or y=3x+0
It is:- 3x+4y = 8 4y = -3x+8 y = -0.75x+2 So the slope is -0.75 and the y intercept is 2
y = 2/3x - 2
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5
Algebraically rearrange both lines to ' y = ''' Hence y = 3x & 3y = x => y = (1/3)x Since the two lines are now y = 3x & y = (1/3)x The lines y = 3x has the greater/steeper slope at '3' , Whereas the other line has a slope of ' 1/3 '. (much less steep).
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3
y-2 = -3x ok you need to rewrite this in the form of y = mx+c where m = slope and c = y intercept y = -3x+2 slope = -3 y intercept = 2
Slope=3, y-intercept=0. y=3x or y=3x+0
Solve for y and the number in front of the x will be your slope.3x-y+2=0assuming no parentheses.-y=-3x-2y=3x+2slope=>3 and the y-intercept is (0,2)
The slope of y is -3x, hope that help
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-3
It is:- 3x+4y = 8 4y = -3x+8 y = -0.75x+2 So the slope is -0.75 and the y intercept is 2
y = 2/3x - 2