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What is the smallest angle and area of a triangle with sides of 6.4 cm by 5.7 cm by 8.2 cm?
Wiki User
∙ 6y ago
Using trigonometry its smallest angle is 43.84 degrees and its area is 18.2 square cm
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Using the cosine rule to find the angle:
a² = b² + c² - 2bc cos A
→ cos A = (b² + c² - a²)/(2bc)
→ A = arccos ((6.4² + 8.2² - 5.7²)/(2 × 6.4 × 5.7)) ≈ 43.8°
Area = ½ × b × c × sin A ≈ ½ × 6.4 cm × 8.2 cm × sin 43.8° ≈ 18.2 cm²
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoIt is 43.8 degrees.
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