The square root of -56 is 56i. i being the letter i, not the number 1. The rules apply for the S.R for all minus numbers - it's always that number + i.
For example;
the square root of -12 = 12i
And the S.R of -98765 = 98765i
SIMPLE!!
* * * * *
SIMPLE? No, it is totally wrong!
sqrt(-56) = i*sqrt(+56) = ±7.483i
The square root of 3136 is 56.
The square root of 56 is irrational. This is because 56 can be expressed as 4 times 14, and while the square root of 4 is rational (2), the square root of 14 is not a perfect square and is therefore irrational. Thus, the combined result of √56 remains an irrational number.
No, the square root of 56 is not an integer. The square root of 56 can be simplified to 2√14, which is an irrational number. Since it cannot be expressed as a whole number, it does not qualify as an integer.
Square root of 56 = Square root of (4 x 14) = (Square root of 4) x (Square root of 14) = 2 x (Square root of 14) The actual value would be 2 x 3.741 = 7.482
2 square root of 14
sqrt(56) = 7.483 approx.
± 7.483315
56
Root 56 = 7.483314773547882 = 7.48
square root of 3136, square root 3146 56x56
in decimal form the answer is 18.7082869
"7" is the number because its square root is "49" & 49+7=56