sum = 0; for (int i = 12; i
What is the sum of 0 + 6
0
6 + 0 + 36 = 42
Nine hundred thirty (930) is the highest three digit number whose digits have a sum of 12. 9+3+0=12. Any numbers higher than that will give you an sum greater than 12.
The sum of a number and its negative (additive inverse) is zero. For any nonzero value n, n + (-n) = 0
Average = Sum/6 = 30
i=0 j=0 sum=1 limit = ARGV[0] while sum < limit print sum i = j j = sum sum = i + j end
Right now, there is no solution. The sum of 2n and 12 will vary according to the value of n. If 2n + 12 = 0, then n = -6
The sum of 12 and 132 is 144
The sum of 21 and 12 is 33.
It is 0.