...int sum = 0;for (int i = 101; i
Mutliplied two prime numbers to get 400?
-7-(-7)=0
Would be that number. Example: 7+0= 7 0+7=7
843.3719
(7 to 50).filter(_ % 2 == 0).sum
public static void main(String[] args) { int count = 0; int sum = 0; for(int i = 100; i < 200; i++) { if(i%7 == 0){ System.out.println(i); count++; sum = sum + i; } } System.out.println("Number of values divisble by 7 is: " + count); System.out.println("Sum of the values divisible by 7 is: " + sum); }
I assume you mean the additive inverse. The sum of any number and its additive inverse is zero. For example, 7 + (-7) = 0.
The sum of these numbers is 38. There are 8 numbers. The mean is thus:38/8 = 4.75
18
Any integer greater than +7.
int num = 0; int sum = 0; // 105 is the first integer greater than 100 which is evenly divisible by 7 for(int i = 104; i < 200; i+=7) {++num;sum += i; }