It is: 5+1 = 6
The sum of all numbers between 1 and 5 is infinite.The sum of whole numbers between 1 and 5 is 2 + 3 + 4 = 9
200 + {(5 + 6) / 1} = 211
The formula to sum a series of numbers is: sum = 1/2 x number_of_numbers x (first_number + last_number) So to sum the integers 5 to 500: From 5 to 500 there are 500 - 5 + 1 = 496 integers, so sum = 1/2 x 496 x (5 + 500) = 125240
(9 + 15)/(-5 + 1) = 24/-4 = -6.
5 you retards
1+1+1+1+1+=5 * * * * * The question did not ask for the sum of the first counting number five times! The sum of the first 5 counting numbers is 1+2+3+4+5 = 15. Such sums are known as triangular numbers.
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
This equals 6, if you are referring to the sum.
9
-1
The sum of the first 5 numbers is 15. 1+2+3+4+5=15
6