Which is n/2(2a + (n - 1)d) where a is the first term, d is the difference between the terms and n is how many terms there are.
a = 31
d = 1
n = 29
29/2(62 + 28) = 29 x 45 = 1305
31 + 59 = 90
59 = 47 + 7 + 5, 59 = 41 + 13 + 5, 59 = 31 + 23 + 5, and there are more.
which three prime numbers have a sum of 59
The sum of the prime numbers is: 31+37+41+43+47+53+59 = 311
They are: 31+37+41+43+47+53+59 = 311The sum of all prime numbers between 30 and 60 is 311.
31 37 41 43 47 53 59
17 + 19 + 23 = 59
13 + 17 + 29 = 59
31 + 37 + 41 + 43 + 47 + 53 + 59 + 61 + 67 = 439
They are: 31+37+41+43+47+53+59 = 311The sum of all prime numbers between 30 and 60 is 311.
The sum of all odd numbers from 1 to 59 can be calculated using the formula for the sum of an arithmetic series. The series consists of the first 30 odd numbers (1, 3, 5, ..., 59). The sum can be calculated as ( S = n/2 \times (first\ term + last\ term) ), where ( n ) is the number of terms. Thus, the sum is ( 30/2 \times (1 + 59) = 15 \times 60 = 900 ).
67 + 3 59 + 11 53 + 17 47 + 23 41 + 29 39 + 31