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Q: What is the surface area of a cube 4 inches x 3 inches x 8 inches?

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The surface area is 54 square inches.

54 square inches.

54 square inches.

It is: 3*3*6 = 54 square inches

The cube's edges measure 3 inches, the surface area of the cube is 54 square inches and the diagonal space of the cube is 5.196 inches.

SA = 54 square inches.

32=9 9x6=54 square inches

The minimum surface area is 6*95(2/3) = 124.92 sq inches.

Such a cube has six sides of 3" by 3" (9 square inch) squares. So the total is 6 x 9 square inches, which is 54 square inches.

A cube has 6 sides. 54 / 6 = 9 square inches per side sqrt(9) = 3 (3 squared = 9) Therefore, each side of the cube is 3 inches. To find the cube's volume, you cube 3: 3 * 3 * 3 = 27 Therefore, the cube has a volume of 27 cubic inches.

512^1/3 = 8 (inch) = length per side of cube82 = 64 = (sq inches) Area per side. There are 6 sides in a cube.64*6=384 (sq inches) Answer384 square inches surface area in a cube of volume 512 cubic inches.

If a cube has sides of length x inches, its surface area is 6*x2 sq inches. So 6*x2 = 96 x2 = 16 so that x = 4 inches = 4/12 feet = 1/3 ft. Then the volume is (1/3)3 = 1/27 cubic feet.

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