answersLogoWhite

0


Best Answer

Point of contact: (21, 8)

Equation of circle: x^2 -y^2 -8x -16y -209 = 0

Completing the squares: (x-4)^2 +(y-8)^2 = 289

Centre of circle: (4, 8) and its radius is 17

Slope of radius: 0

Slope of tangent: 0

Tangent equation of the circle: x = 21 meaning that the tangent line is parallel to the y axis and that the radius is parallel to the x axis.

User Avatar

Wiki User

6y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

6y ago

x2 -y2 -8x -16y -209 equals 0 cannot be the equation of a circle. so the question does not make make sense.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the tangent equation that touches the circle x2 -y2 -8x -16y -209 equals 0 at the point of 21 and 8 on the Cartesian plane?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Tangent of a circle is what?

A tangent of a circle is a straight line that touches the circle at only one point.


What is the tangent line equation of the circle x2 plus y2 -8x -16y -209 equals 0 when it touches the circle at 21 8 on the Cartesian plane?

Equation of circle: x^2 +y^2 -8x -16y -209 = 0 Completing the squares: (x-4)^2 +(y-8)^2 = 289 Radius of circle: 17 Center of circle: (4, 8) Point of contact: (21, 8) Slope of radius: 0 Slope of tangent line: 0 Equation of tangent line: x = 21 which means it touches the circle at (21, 0) which is a straight vertical line parallel to the y axis


What is the Cartesian equation of a circle whose centre is in the 1st quadrant with a radius of 7 and touches the x and y axes?

Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49


A line that touches a circle?

Tangent


What is the tangent of a circle?

A tangent is a straight line that touches a circle's circumference at one point


How do you find the tangent of a circle?

a tangent is a line that touches the circle at only ONE point


What is the tangent equation of the circle 2x squared plus 2y squared -8x -5y -1 that touches the point of 1 -1 on the Cartesian plane?

If you mean: 2x^2 +2y^2 -8x -5y -1 = 0 making contact at (1, -1) Then the tangent equation in its general form works out as: 4x+9y+5 = 0


Definition of tangent in a circle?

A tangent to a circle is a line from a point outside the circles which touches the circle at a single point.


How can you recognize a tangent of a circle?

A tangent of a circle is a straight line that touches the circle's circumference at just one point.


What is the straight line which touches the circumference in a circle?

It is the tangent of the circle


What does '' a tangent to a circle '' mean?

It is a straight line that touches the circle.


What is the tangent equation that touches the circle of x squared plus y squared -8x -y plus 5 equals 0 at the point of 1 2 on the Cartesian plane showing work?

Equation of circle: x^2 +y^2 -8x -y +5 = 0Completing the squares: (x-4)^2 +(y-0.5)^2 = 11.25Centre of circle: (4, 0.5)Slope of radius: -1/2Slope of tangent: 2Equation of tangent: y-2 = 2(x-1) => y = 2xNote that the above proves the tangent of a circle is always at right angles to its radius