6x-y=-14 2x-3y=6
eqn 1 Y = 2X + 6 eqn 2 2X - Y = 2 Rearrange eqn2 to isolate Y eqn2 Y = 2X - 2 so 2X + 6 = 2X - 2 subtracting 2X from both sides we get 6 = -2 As this is impossible this set of equations can not be solved.
[ y = -2x + any other number ] is parallel to [ y = -2x + 6 ].
y=2x/6 26=2x/6 26x6=156. 156/2=78. x=78
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
If: y = x+6 and y = 2x Then: x+6 = 2x And: 6 = 2x-x => 6 = x So: x = 6 and y = 12
No but y = -1/2x+3 is perpendicular to y = 2x+6
6x-y=-14 2x-3y=6
eqn 1 Y = 2X + 6 eqn 2 2X - Y = 2 Rearrange eqn2 to isolate Y eqn2 Y = 2X - 2 so 2X + 6 = 2X - 2 subtracting 2X from both sides we get 6 = -2 As this is impossible this set of equations can not be solved.
[ y = -2x + any other number ] is parallel to [ y = -2x + 6 ].
y=2x/6 26=2x/6 26x6=156. 156/2=78. x=78
2x + 4 = y ...............2x + 4 = y ....................2x + 4 = y .............2*(-6)+ 4 = y x - y = 2 .......<=> ...x - 2x - 4 = 2 .....<=> ...x = -6......... <=>.... x = -6 ..............<=> y = - 8 x = - 6
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
Yes. 6 - y = 2x -y = 2x -6 y= -2x +6 If plotted on a graph, the line will have a gradient -2, and will intercept the axes at (0,6) and (3,0).
4
-4
3x-y = 3y3x = 4yy = 0.75x3x-0.75x = 2x+22.25x = 2x+20.25x = 2x = 8y = 6