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Let the angles of the triangle be A B C and their opposite sides be a b c respectively then by using the cosine rule by a method of 'give and take' the value of X works out as 16cm. Check by using the cosine rule: (10^2 +16^2 -14^2)/(2*10*16) = 60 degrees

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For a triangle ABC with sides a, b, c with side a opposite angle A, etc:

a² = b² + c² - 2bc cos A

Assuming the 60° angle (A) is opposite the side with length x - 2 cm (a), then:

(x - 2)² = x² + 10² - 2.10.x.cos 60°

→ x² - 4x + 4 = x² + 100 - 20x.½

→ 10x - 4x = 100 - 4

→ 6x = 96

→ x = 16

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6y ago

If x = 8.86 cm then the angle opposite x is 60 degrees.

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Q: What is the value of X when a triangle has sides of 10cm Xcm and X-2cm whose opposite angle is 60 degrees?
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