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The x-intercept of the line given by the equation y = 5x - 10 is the point ( 2, 0 )

The x-intercept is where the line crosses the x-axis. Any point on the x-axis has an y value of 0. This gives us the y coordinate, as well as the following equation:

0 = 5x - 10

Solve for x.

First, we add 10 to both sides.

10 + 0 = 5x - 10 + 10

Simplify

10 = 5x

Now we divide both sides of the equation by 5, giving us

10 / 5 = (5x) / 5

Simplify

2 = x.

Ergo, the point is ( 2, 0 )

Q: What is the x-intercept of y5x-10?

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As written this is not a graphable thing. I does not represent a graphable equation because there is no "=" sign. Whatever the equation might be, the x intercept is found by setting y=0, which leaves you with an equation for x, which is the intercept.

First, put the equation in slope-intervcept form y=mx + b 5y=4x + 40 The y intercept is where x=0 so- 5y= 4(0) +40 solve for y y intercept = (0,8) For the x intercept, y=0 0=4x+40 -4x=40 x= -10 xintercept =( -10.0)

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-3

As written this is not a graphable thing. I does not represent a graphable equation because there is no "=" sign. Whatever the equation might be, the x intercept is found by setting y=0, which leaves you with an equation for x, which is the intercept.

To find the x-intercept for 5x - 4y = 18, plug in a 0 for the y value and solve for x. 5x - 4(0) = 18 5x = 18 x = 18/5 or 3.6 The line will hit the x-axis at (3.6,0)

First, put the equation in slope-intervcept form y=mx + b 5y=4x + 40 The y intercept is where x=0 so- 5y= 4(0) +40 solve for y y intercept = (0,8) For the x intercept, y=0 0=4x+40 -4x=40 x= -10 xintercept =( -10.0)