X-intercept=3 y-intercept=-2
-2
4x-2y = 12 -2y = -4x+12 y = 2x-6 Therefore the y intercept is -6 and the slope is 2
x-intercept of y equals -4x plus 4 y = -4x + 4 0 = -4x + 4 -4 = -4x 1 = x So 1 is the x-intercept
0, -2
X-intercept=3 y-intercept=-2
-2
4x-2y = 12 -2y = -4x+12 y = 2x-6 Therefore the y intercept is -6 and the slope is 2
Solve for Y algebraically. 4X + 8Y = 16 8Y = - 4X + 16 Y = - 1/2X + 2 graph and see that the Y intercept = 2
When finding the y-intercept, plug in x=0 y = 4x + 2 y = 4(0) + 2 y = 2 So your intercept is (0,2)
x-intercept of y equals -4x plus 4 y = -4x + 4 0 = -4x + 4 -4 = -4x 1 = x So 1 is the x-intercept
0, -2
y=4x+2
The y intercept is -6
Y- intercept of 4x+8y=16
4x+2y = 12 2y = -4x+12 y = -2x+6 So the y intercept is 6 and the slope is -2
y = -4x The y-intercept is zero. That is, the graph passes through the origin.